Overview
Compact operators recover a useful part of finite-dimensional behavior inside infinite-dimensional spaces. Their inputs may range over a bounded family with no convergent subsequence, yet their outputs always admit one. This extra control underlies existence arguments, integral equations, and the discrete spectral description of compact self-adjoint operators.
Compactness concerns the operator together with its domain and codomain norms. The same formula can behave differently when the function spaces change, so a statement that an operator is compact must name those spaces.
Prerequisites
Know Banach spaces, bounded linear maps, and norm convergence. A set is relatively compact when its closure is compact. In metric spaces this can be checked using sequences. In a complete metric space, total boundedness is equivalent to relative compactness; total boundedness means that finitely many balls of any prescribed positive radius cover the set.
Definition and conventions
For Banach spaces , a linear map is compact if has compact closure in for every bounded . It suffices to test the closed unit ball .
Equivalently, every bounded sequence in has a subsequence for which converges in the norm of . The inputs themselves need not converge. Since relatively compact sets are bounded, this definition implies that is a bounded operator. The image need not be closed for general Banach domain spaces.
Intuition
A compact operator makes its unit-ball image approximable, at each resolution, by finitely many output points. This does not say that its range is finite-dimensional. Instead, infinitely many directions may survive while their effects become progressively smaller. The shrinking diagonal operator below makes that distinction concrete.
Examples and non-examples
On , indexed by , set . Let retain only the first output coordinates. Then has finite rank and
The upper bound follows by summing squared coordinates; equality follows by using . Therefore is compact as an operator-norm limit of compact operators, although its range contains every finitely supported sequence and has infinite dimension.
The identity on an infinite-dimensional Hilbert space is bounded but not compact: an orthonormal sequence is bounded and its distinct terms stay distance apart. It has no norm-convergent subsequence.
For a continuous kernel on , the operator is compact from to itself. Bounded inputs produce uniformly bounded, equicontinuous outputs, so Arzelà–Ascoli applies. Continuity of the kernel is a sufficient hypothesis in this example, not part of the definition of compactness.
Important properties
Every bounded finite-rank operator is compact. Operator-norm limits of compact maps into a Banach space are compact as well. For a proof sketch, approximate the image of the unit ball uniformly by a compact operator's image, cover that image by finitely many small balls, and obtain total boundedness. Completeness of the codomain then gives compact closure.
Composing a compact map on either side with compatible bounded linear maps preserves compactness. Bounded maps preserve bounded sets, and continuous maps preserve compact sets, which explains the two compositions.
If converges weakly to , a compact operator satisfies in norm. Weakly convergent sequences are bounded. Any norm-convergent subsequence of their images must have limit , since bounded linear functionals distinguish points. A subsequence staying a fixed distance from would contradict compactness.
Connections and further reading
For the zero-Dirichlet Laplacian on a bounded smooth domain, the solution operator maps boundedly into ; the compact inclusion back into makes it compact. This connects weak PDE solutions with spectral theory. Hunter, §4.8 gives this mechanism for elliptic resolvents; Erdman, §7.1 develops the operator framework.